Thursday, June 6, 2019
Molarity and Percent Solution Lab Essay Example for Free
 Molarity and  share Solution Lab EssayObjectiveThe  object lens of this lab was to determine the megabyte and percent solution of a solution with an  inexplicable  meanness.BackgroundMolarity is the number of moles of a solute per liter of a solution. Percent solution is the percentage of a solute in a specific  stack or volume of a solvent. A solute is a solid that gets dissolved in a solvent or a liquid that is a smaller amount than the solvent. A solvent is a liquid that dissolves the solute and it always is a bigger amount.     Solvation is when solute particles are surrounded by solvent molecules. A lab technique that was used during the lab was to boil the solution in order to separate the solute from the solvent.Materials  contention 10mL  graduate cylinder Solution with unknown concentration Hot plate Pipette Hot grip Scale 100mL beakerProcedure1. Obtain the solution with the unknown concentration from Mrs. Magdaleno. 2. Measure the volume of the solution by pouring it in th   e 10mL graduated cylinder. Use the pipette to take out solution in the graduated cylinder until the volume was at 6mL. Record it in the data table. 3. Measure the empty 100mL beaker using the scale. Record it in the data table. 4. Pour the solution in the 100mL beaker.5. Find the mass of the beaker and solution using the scale. Make sure to subtract original beaker mass from the mass of the beaker and solution. 6. Boil the solution to separate the solute from the solvent by using the hot plate set to nine. 7. Once all the water has  vanishd use the hot grips to remove the beaker from the hot plate and let cool. Find the mass of the beaker and solute using the scale. Make sure to subtract beaker mass from the beaker and solute mass. 8. Use the data from the data table to solve for molarity and percent solution.Observations The water started to boil and evaporate when it was on the hot plate. It smelt like the salt was burning. Some salt spilled out on the lab station when the water c   ompletely evaporated.Data  evadeVolume of solution (L) 6mL=0.006L  Mass of beaker (g) 68.95g  Mass of solution and beaker(g) 75.06g  Mass of solution(g) 6.12g  Mass of solute and beaker(g) 69.41g  Mass of solute(g) 0.46g ResultsA MolarityB Percent SolutionConclusionThe molarity that was calculated for the unknown solution was 1.31M. The percent solution that was calculated for the unknown solution was 7.52%. A procedural that would have led to a lower concentration value was when some salt spilled out onto the lab station after all of the water had evaporated from the beaker. Another error that would result in a  high concentration would be if the beaker was not dry when the mass was measured with the scale. Something that could be done differently to lead to a more accurate concentration would be to take the beaker off the hot plate sooner and not let the salt sit and burn or come out of the beaker.  
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